-2x^2+75x-3=0

Solution for -2x^2+75x-3=0 equation:

-2x^2+75x-3=0

a = -2; b = 75; c = -3;
Δ = b2-4ac
Δ = 752-4·(-2)·(-3)
Δ = 5601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{5601}}{2*-2}=\frac{-75-\sqrt{5601}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{5601}}{2*-2}=\frac{-75+\sqrt{5601}}{-4}
$